2(x^2+8-120)=0

Solution for 2(x^2+8-120)=0 equation:

2(x^2+8-120)=0

We multiply parentheses

2x^2+16-240=0

We add all the numbers together, and all the variables

2x^2-224=0

a = 2; b = 0; c = -224;
Δ = b2-4ac
Δ = 02-4·2·(-224)
Δ = 1792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1792}=\sqrt{256*7}=\sqrt{256}*\sqrt{7}=16\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{7}}{2*2}=\frac{0-16\sqrt{7}}{4}
=-\frac{16\sqrt{7}}{4}
=-4\sqrt{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{7}}{2*2}=\frac{0+16\sqrt{7}}{4}
=\frac{16\sqrt{7}}{4}
=4\sqrt{7}
$